WebStep 1: Definition. An erg is the amount of work done by exerting a force of one dyne across a one-centimeter distance. It will be one gram centimeter-squared per second-squared throughout CGS base units. A joule seems to be the amount of work done by … Express joule in terms of erg. Question. Express joule in terms of erg. Video … WebThe answer is 10000000. We assume you are converting between erg and joule. You can view more details on each measurement unit: erg or joule The SI derived unit for energy …
Derive a relationship between S.I and C.G.S unit of work.
WebAug 23, 2024 · SI units: 1.000000×10−7 J. Derivation: 1 erg = 1 dyn⋅cm. Joule is the SI unit of energy while erg is the cgs unit of energy. Therefore, 1 Joule is equal to 107 erg. One joule equals the work done (or energy expended) by a force of one newton (N) acting over a distance of one meter (m). WebRelation between joule and erg: 1 joule = 1 N × 1 m But 1 N = 10 5 dyne And 1 m = 100 cm = 10 2 cm Hence, 1 joule = 10 5 dyne × 10 2 cm = 10 7 dyne × cm = 10 7 erg Thus, 1 Joule = 10 7 erg Concept: Work Done by the Force of Gravity (W = mgh) Is there an error in this question or solution? robert w hoffmann
Convert 10 Joules to erg using the dimensional method.
WebRelation between joule and erg : 1 joule =1N×1m But 1N=10 5dyne And 1m=100cm=10 2cm Hence. 1joule=10 5dyne×10 2cm =10 7dyne×cm=10 2erg Thus, 1Joule=10 7erg Was this answer helpful? 0 0 Similar questions Which of the following will give 1J of work? Medium View solution > The c.g.s. unit of work is Easy View solution > View more The erg is a unit of energy equal to 10 joules (100 nJ). It originated in the Centimetre–gram–second system of units (CGS). It has the symbol erg. The erg is not an SI unit. Its name is derived from ergon (ἔργον), a Greek word meaning 'work' or 'task'. An erg is the amount of work done by a force of one dyne exerted for a distance of one centimetre. In the CGS base units, it is equal to one gram centimetre-squared per second-squared (g⋅cm /s ). … WebLet us start with the Joule coefficient. Here we are interested in how the temperature changes with volume in an experiment in which the internal energy is constant. That is, we want to derive the Joule coefficient, η = (∂ T /∂ V) U. Now entropy is a function of state – i.e. of the intensive state variables P, V and T. ( V = molar volume.) robert w holland